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Write the code (from to )using for loop andif elseif statementto accept themobile phone numbersof200 residents of Dubaiasstringand check if thelength of eachmobile number is10. Depending on the first 3 characters of the mobile number,display the messagefrom the table below:First 3 charactersMessage“050”, “054”, “056”Etisalat number“052”,“055”, “058”DunumberFor anyother input(if the phone number is not a ten digit number or if it does not start with any of the above digits)Not a valid mobile number

Sagot :

MrRoyal

Answer:

In Python:

nos = int(input("How many phone number: "))

for i in range(1,nos+1):

   phn = input("Phone Number: ")

   if not len(phn) == 10:

       print("Invalid")

   else:

       charactersMessage = phn[0:3]

       if charactersMessage in ['050', '054', '056']:

           print("Etisalat Number")

       elif charactersMessage in ['052', '055', '058']:

           print("Du Number")

       else:

           print("Invalid")

Explanation:

Prompts the user for the frequency of phone numbers to check

nos = int(input("How many phone number: "))

This iterates through the phone numbers

for i in range(1,nos+1):

This prompts the user for phone number

phn = input("Phone Number: ")

Prints invalid id number length is not 10

if not len(phn) == 10:

   print("Invalid")

If otherwise

else:

This gets the first 3 characters

   charactersMessage = phn[0:3]

Prints Etisalat number if the characters are either 050, 054 or 056

   if charactersMessage in ['050', '054', '056']:

       print("Etisalat Number")

Prints Du number if the characters are either 052, 055 or 058

   elif charactersMessage in ['052', '055', '058']:

       print("Du Number")

Prints error if otherwise

   else:

       print("Invalid")

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