Answer:
2( x +2 )
x+1
Step-by-step explanation:
to add or subtract expressions expand them to make their denominators the same, multiply 1 time [tex]\frac{x-2}{x-2}[/tex]
since [tex]\frac{x}{x-2}[/tex] and [tex]\frac{x-2}{x-2}[/tex] have the same denominators add them by adding their numerators
combine x + x -2
factor [tex]x^{2}[/tex] - 4
to add or subtract expressions expand them and multiply by 1
have same denominator add them by adding their numerators
do the multiplications in 3 + ( x-2 )(x+2)
combine like terms in 3 + [tex]x^{2}[/tex] + 2x - 2x -4
divide [tex]\frac{2x-2}{x-2}[/tex] by [tex]\frac{-1 + x^{2} }{(x-2)(x+2) }[/tex] multiplying [tex]\frac{2x-2}{x-2}[/tex]
cancel out x-2 in both numerator and denominator
factor the expression that are not already factored
cancel out x-1 in both numerator and denominator
expand the expression
