Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Explanation:
Average atomic mass of Chlorine = 35.45 amu
The percentage of isotopes is the percentage abundance.
This is given by;
Average atomic mass = (Mass of isotope * Percentage abundance of 35/17 Cl) + (Mass of isotope * Percentage abundance 37/17 Cl)
Let percentage abundance of 35/17 Cl = x
Then percentage abundance of 37/17 Cl = 1 - x
Putting the values in the equation;
35.45 = (35 * x) + (37 * (1-x))
35.45 = 35x + 37 - 37x
35.45 - 37 = 35x - 37x
- 1.55 = -2x
x = 1.55 / 2 = 0.775
Percentage abundance of 35/17 Cl = 0.775 * 100 = 77.5%
Percentage abundance of 37/17 Cl = (1 - 0.775) * 100 = 22.5%
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
