Answer:
see the answers
Step-by-step explanation:
to understand this
you need to know about:
tips and formulas:
- L.C.D=lowest common denominator
let's solve:
[tex]1) \sf\frac{7}{m - 6} \: , \frac{1}{m} \\ [/tex]
denominators are m-6,m
therefore
the lowest common denominator is
(m-6)(m)
[tex] \sf\frac{1}{n - 1} \: , \frac{1}{ {n}^{2} - 2n + 1 } [/tex]
denominators n-1,n²-2n+1
step-1
factor n²-2n+1 to find the lowest common denominator
- use (a-b)²=a²-2ab+b to factor n²-2n+1
therefore
- (n)²-2.n.1+(1)²
- (n-1)²
therefore
the L.C.D of the second expression is
(n-1)²
alternative form
(n-1)(n-1)
[tex]3) \tt\frac{k}{ {h }^{2} - 5h + 6} \: , \frac{3}{h -3 } [/tex]
step-1
factor out h²-5h+6 to find L.C.D
- rewrite -5h as -2h-3h: h²-2h-3h+6
- factor out h: h(h-2)-3h+6
- factor out -3: h(h-2)-3(h-2)
- group: (h-3)(h-2)
therefore
the L.C.D of the third expression is
(h-3)(h-2)
