Answered

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2.
What is the distance between the points (2,0) and (-6, 6) on the standard (x, y) coordinate plane?
F
27
G
2/13
H
8
10
K
2137

Sagot :

mathstudent55

Answer:

10

Step-by-step explanation:

Use the distance formula.

[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

We have x1 = 2; y1 = 0; x2 = -6; y2 = 6.

[tex] d = \sqrt{(-6 - 2)^2 + (6 - 0)^2} [/tex]

[tex] d = \sqrt{(-8)^2 + 6^2} [/tex]

[tex] d = \sqrt{64 + 36} [/tex]

[tex] d = \sqrt{100} [/tex]

[tex] d = 10 [/tex]

Answer: 10

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