Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.


Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph of the equation.
(4,−3); y=3x−5

Sagot :

theleangreenbean

Answer:

[tex]y=3x-15[/tex]

Step-by-step explanation:

Slope intercept form: [tex]y=mx+b[/tex] where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept (the value of y when the line crosses the y-axis)

1) Find the slope of the line ([tex]m[/tex])

When it comes to parallel lines, they will always have the same slope but different y-intercepts. The given equation is [tex]y=3x-5[/tex]. Because 3 is in the place of m, we know that the slope of the line is 3. Therefore, the slope of the line parallel to it will also be 3. So far, this is what our equation looks like:

[tex]y=3x+b[/tex]

2) Find the y-intercept ([tex]b[/tex])

To find the y-intercept, we plug the given point (4,-3) into the equation we currently have and solve for b.

[tex]y=3x+b\\-3=3(4)+b\\-3=12+b[/tex]

Subtract both sides by 12

[tex]-3-12=12+b-12\\-15=b[/tex]

Therefore the y-intercept of our line is -15. Plug -15 back into the original equation as b.

[tex]y=3x+(-15)\\y=3x-15[/tex]

I hope this helps!

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.