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Glenn shoots an arrow at a 30.0 degree angle. It has a velocity of 65.0 m/s.

How far will the arrow travel? *

Sagot :

onyebuchinnaji

Answer:

The horizontal distance traveled by the projectile is 373.36 m.

Explanation:

Given;

angle of projection; θ = 30⁰

initial velocity of the projectile, u = 65 m/s

The horizontal distance traveled by the projectile or range of the projectile is calculated as;

[tex]R = \frac{u^2 \times sin(2\theta)}{g} \\\\R = \frac{65^2 \times sin(2\times 30^0)}{9.8}\\\\R = \frac{4225\times sin(60)}{9.8} \\\\R = 373.36 \ m[/tex]

Therefore, the horizontal distance traveled by the projectile is 373.36 m.

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