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Sagot :
Answer:
a) 26.79%, b) 50.42% and c) 22.79%
Step-by-step explanation:
a. What is the probability that both Dave and Mike will show up?
As decisions of showing up can be assumed to be independent, the probability will be given by
(1-0.53)(1-0.43)=(0.47)(0.57)=0.2679=26.79%
b. What is the probability that at least one of them will show up?
There are two possibilities for this to happen:
Dave shows up but Mike does not. The probability of Dave to show up is (1-0.53)=0.47 and the probability that Mike does not is 0.43. Then, as these events are independent, the probability for both of them to happen is (0.47)(0.43)=0.2021=20.21%
Mike shows up but Dave does not. The probability of Mike to show up is (1-0.43)=0.57 and the probability that Mike does not is 0.53. Then, as these events are independent, the probability for both of them to happen is (0.57)(0.53)=0.3021=30.21%
Therefore, the probability that at least one of them will show up? is 20.21%+30.21%=50.42%.
c. What is the probability that neither Dave nor Mike will show up?
As decisions of showing up can be assumed to be independent, the probability will be given by
(0.53)(0.43)=0.2279=22.79%
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