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Sagot :
Answer:
The right solution is "0.50 m/s²". A further explanation is provided below.
Explanation:
The given values are:
Mass,
m = 50 kg
Speed,
v = 10 m/s
Rolling friction acting backward (south),
f = 10 N
Air resistance acting backward (south),
[tex]F_T[/tex] = 15 N
The total force acting will be:
⇒ [tex]F = -f-F[/tex]
On substituting the given values, we get
⇒ [tex]=-10-15[/tex]
⇒ [tex]=-25 \ N[/tex]
Now,
⇒ [tex]a = \frac{F}{m}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{-25}{50}[/tex]
⇒ [tex]=-0.50 \ m/s^2[/tex]
The horizontal acceleration will be "0.50 m/s²" because the (-)ve sign indicates it in south direction.
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