Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A 2.0-kg mass is projected from the edge of the top of a 20-m tall building with a velocity of 24 m/s at some unknown angle above the horizontal. Disregard air resistance and assume the ground is level. What is the kinetic energy of the mass just before it strikes the ground?

Sagot :

Answer:

968 J

Explanation:

The computation of the kinetic energy is shown below:

Given that

mass m = 2 kg

height h = 20 m

velocity v = 24 m / s

Now

According to the law of conservation of energy ,

= K.E at top + P.E at top

= ( 1 ÷ 2) mv ^ 2 + mgh

= 576 + 392

= 968 J

onyebuchinnaji

The kinetic energy of the mass just before it strikes the ground is 968 J.

The given parameters:

  • Mass of the object, m = 2.0 kg
  • Height of the building, h = 20 m
  • Initial velocity of the mass, u = 24 m/s

The kinetic energy of the mass just before it strikes the ground is calculated by applying the principle of conservation of energy;

[tex]K.E_f = K.E_ i + P.E_i\\\\K.E _f = \frac{1}{2} mv^2 + mgh\\\\K.E_f = \frac{1}{2} \times 2\times 24^2 \ + \ 2 \times 9.8 \times 20\\\\K.E_f = 968 \ J[/tex]

Thus, the kinetic energy of the mass just before it strikes the ground is 968 J.

Learn more about conservation of energy here: https://brainly.com/question/166559

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.