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Determine the number of molecules of OF2 and moles of fluorine contained in 5.53 moles of OF2.

Sagot :

Answer: [tex]33.31\times 10^{23}[/tex] molecules of [tex]OF_2[/tex]  

and 11.06 moles of Flourine

 Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

1 mole of [tex]OF_2[/tex] contains= [tex]6.022\times 10^{23}[/tex]  molecules of [tex]OF_2[/tex]

Thus 5.53 moles of [tex]OF_2[/tex] contains=[tex]\frac{6.022\times 10^{23}}{1}\times 5.53=33.31\times 10^{23}[/tex] molecules of [tex]OF_2[/tex]  

1 mole of [tex]OF_2[/tex] contains= 2 moles of Flourine

5.53 moles of [tex]OF_2[/tex] contains=[tex]\frac{2}{1}\times 5.53=11.06[/tex] moles of Flourine