Answered

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If a solution containing 24.0 g of a substance reacts by first-order kinetics, how many grams remain after three half-lives?

Sagot :

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Answer:

3.0g remain

Explanation:

The half-life is defined as the time required for a reactant to decrease its concentration in exactly the half of the initial amount of reactant. Having this in mind:

In one half-life, the mass will be:

24.0g / 2 = 12.0g

In two half-lifes:

12.0g / 2 = 6.0g

And in three half-lifes, the mass that remain is:

6.0g / 2 =

3.0g remain

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