Answered

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A cork dropped into a water filled beaker floats with volume V1 representing the portion of cork above water. When it is dropped in a beaker containing corn syrup, it floats with its volume V2 (again, the portion of cork above syrup). How do these volumes compare?A. V1 = V2.B. V1 > V2.C. V1 < V2.D. V1 ≥ V2.

Sagot :

Answer:

C. V1 < V2

Explanation:

The computation is shown below:

As we know that

Byoyancy force represent the displaced water weight

[tex]B = V_{in},_{w}P_{w}g[/tex]

[tex]V_{in},_{w}[/tex] denotes cork volume that inside the water

[tex]P_{w}[/tex] denotes water density

And, byoyancy force represent the displaced weight of corn syrup

[tex]B = V_{in},_{syr}P_{syr}g[/tex]

[tex]V_{in},_{syr}[/tex] denotes the cork volume that inside the water

[tex]P_{syr}[/tex] denotes syrup density

Now

[tex]P_{syr}>P_{w}\\\\V_{in},_{syr}<V_{in},_{wat}\\\\V_2>V_1 or V_1 <V_2[/tex]

Hence, the option c is correct

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