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Given log34≈1.262 and log37≈1.771, what is the value of log3(167)?



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Sagot :

Answer:

0.753

Step-by-step explanation:

I just took the test lol

The value of log₃(⁷/₁₆) when log₃4 = 1.262 and log₃7 = 1.771 is;

log₃(⁷/₁₆) = -0.753

We are given;

log₃4 = 1.262

log₃7 = 1.771

We want to find log₃(⁷/₁₆)

Now, from properties of logarithm too, we have;

logₐ(x/y) = logₐx - logₐy

Thus;  log₃(⁷/₁₆) =  log₃7 -  log₃16

Also, we know that; logₐx² = 2logₐx

Thus; log₃16 =  log₃4²

log₃16 = 2log₃4

Thus; log₃(⁷/₁₆) = log₃7 - 2log₃4

Plugging in the relevant values gives;

1.771 - 2(1.262) = -0.753

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