Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

What is the remainder if f(x) = x4 – 5x2 - 6x - 10 is divided by x - 3?


Sagot :

Answer:-46

Step-by-step explanation: just took test

The remainder when f(x) is divided by (x - 3) is 8 and this can be determined by using the factorization method.

Given :

[tex]\rm f(x) = x^4-5x^2-6x-10[/tex]

The following steps can be used in order to determine the remainder if f(x) is divided by (x - 3):

Step 1 - Write the mathematical expression of the statement "f(x) is divided by (x - 3)".

[tex]=\dfrac{x^4-5x^2-6x-10}{x-3}[/tex]

Step 2 - Now, try to factorize the numerator in the above expression.

[tex]=\dfrac{x^4-3x^3+3x^3-9x^2+4x^2-12x+6x-18+18-10}{x-3}[/tex]

Step 3 - Further simplify the above expression.

[tex]=\dfrac{x^3(x-3)+3x^2(x-3)+4x(x-3)+6(x-3)+8}{x-3}[/tex]

[tex]=(x^3+3x^2+4x+6) +\dfrac{8}{x-3}[/tex]

So, the remainder when f(x) is divided by (x - 3) is 8.

For more information, refer to the link given below:

https://brainly.com/question/6810544