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Sagot :
Answer:
Explanation:
2HNO₃ + Ba( OH)₂ = Ba( NO₃ )₂ + 2H₂O .
2 mole 1 mole
13.9 mL of .174M barium hydroxide contains .0139 x .174 moles
= 2.42 x 10⁻³ moles .
1 mole of barium hydroxide reacts with 2 moles of nitric acid
2.42 x 10⁻³ moles of barium hydroxide will react with 2 x 2.42 x 10⁻³ moles of nitric acid
= 4.84 x 10⁻³ moles
4.84 x 10⁻³ moles of nitric acid is contained in 28.7 mL
molarity of nitric acid = 4.84 x 10⁻³ / 28.7 x 10⁻³
= .169 M .
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