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Sagot :
Answer:
yes , keiko is correct.
sin^(-1)x = -sin^1
Answer:
Keiko is wrong
Step-by-step explanation:
Keiko is incorrect
When n is positive, 1^n will always be 1
but........ (-1)^n will not always be -1
This is because there are parenthesis around -1
So n is even, then it will be 1 not -1
For example, n = 4
You will do -1 * -1 * -1 * -1 which is 1 not -1
but if n = 3
You will do -1 * -1 * -1 which is -1
Therefore, the second statement is incorrect resulting in Keiko being wrong
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