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What is the distance between the points (2, 3) and (5, -4)?
7.6 units
3.7 units
6.3 units
10 units


Sagot :

irspow

Answer:

Step-by-step explanation:

[tex]d^2=(x_2-x_1)^2+(y_2-y_1)^2\\ \\ d^2=(5-2)^2+(-4-3)^2\\ \\ d^2=3^2+(-7)^2\\ \\ d^2=9+49\\ \\ d^2=58\\ \\ d=\sqrt{58}\\ \\ d\ approx 7.6\ units[/tex]