kkaylynnfaith
Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

PLS HELP!! GIVING BRAINLIST!!

Michael uses a blend of dark chocolate and milk chocolate to make the ice cream topping at his restaurant. He needs to buy 100 kg of chocolate in total for his next order. Dark chocolate costs $12 per kilogram, milk chocolate costs $10 per kilogram, and he wants to spend $1120 total.

Let d be the number of kilograms of dark chocolate he buys and m be the number of kilograms of milk chocolate he buys.

Which system of equations represents this situation?

Sagot :

MiniTIgra

Answer:

d + m = 100

12d + 10m = 1120

Step-by-step explanation:

d = 60

m = 40

desaniamiya101

Answer: 60 kg dark chocolate, 40 kg milk chocolate

Step-by-step explanation:

Okie soooo

Let's name the variables (which they did for us lol)

d = kg of dark chocolate and m = kg of milk chocolate

He needs 100 kg of chocolate

d + m = 100

and he wants to spend 1120 when dark chocolate costs $12/kg and milk chocolate costs $10/kg

12d + 10m = 1120

Now we solve the system (I shall use elimination method)

Multiply the first equation my -10

-10(d + m) = (100)(-10)

which becomes

-10d - 10m = -1000

12d + 10m = 1120 (rewrite the second equation)

------------------------- (add the two equations together)

2d = 120

d = 60

now substitute d into either equation

60 + m = 100

m = 40

60 kg dark chocolate

40 kg milk chocolate

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.