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Sagot :
Answer:
1/36 = 0.0278 = 2.78% probability that you guess the summer's top two must see movies if you randomly guess
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this question, the order in which the movies are chosen is not important, which means that we use the combinations formula to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Desired outcomes:
Top two movies, so only one outcome, which means that [tex]D = 1[/tex]
Total outcomes:
Two movies from a set of 1. So
[tex]T = C_{9,2} = \frac{9!}{2!(9-2)!} = 36[/tex]
Probability:
[tex]p = \frac{D}{T} = \frac{1}{36} = 0.0278[/tex]
1/36 = 0.0278 = 2.78% probability that you guess the summer's top two must see movies if you randomly guess
Answer:
1.39%
Step-by-step explanation:
This is a permutation problem because order matters.
There are 9! ways to rank the summer's must-see movies.
There are (9−2)!=7! ways to choose two movies as the top two must-see movies.
P = 7!/9! = 1/72 = 0.0139
To express our answer as a percent, we multiply by 100:
0.0139 x 100 = 1.39%
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