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The length of a rectangle is

8 inches longer than the

width. If the ratio of the

length to perimeter is 5:16,

what is the area of the

rectangle?


Sagot :

Answer:

Step-by-step explanation:

The area of the rectangle is 240 square inches if the length of a rectangle is  8 inches longer than the width. If the ratio of the length to the perimeter is 5:16.

What is the area of the rectangle?

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

It is given that:

The length of a rectangle is  8 inches longer than the width. If the ratio of the length to the perimeter is 5:16

As we know, the two-dimensional geometry in which the angle between the adjacent sides is 90 degrees. It is a type of quadrilateral.

Let l and w be the length and width of the rectangle:

l = 8 + w

w = l - 8

l/P = 5/16  (the length to the perimeter is 5:16)

P is the perimeter of the rectangle.

P = 2(l + w)

l/[2(l + w)] = 5/16

16l = 10(l + w)

8l = 5(l + l - 8)

8l = 10l - 40

2l = 40

l =20 inches

w = 20 - 8 = 12 inches

Area = 20x12 = 240 square inches

Thus, the area of the rectangle is 240 square inches if the length of a rectangle is  8 inches longer than the width. If the ratio of the length to the perimeter is 5:16.

Learn more about the rectangle here:

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