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Sagot :
Answer:
you have to find 4 spring with this elastic constant k = 316 N / m
Explanation:
In this case for the design of the dispenser the four springs are placed in the four corner at the bottom, therefore we can use the translational equilibrium relationship
4 F_e -W = 0
where the elastic force is
F_e = k x
we substitute
4 kx = mg
k = [tex]\frac{mg}{4x}[/tex]
Each tray has a thickness of x = 0.450 cm = 0.450 10⁻² m, this should be the elongation of the spring so that when the tray is in position it will remain fixed.
let's calculate
k = [tex]\frac{0.580 \ 9.8}{4 \ 0.450 \ 10^{-2} }[/tex]
k = 3.1578 10² N / m
k = 316 N / m
therefore you have to find 4 spring with this elastic constant
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