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Sagot :
Answer:
P-value = 0.0333
At 5% level of significance;
0.0333 < 0.05
Therefore, we reject null hypothesis H₀ at 5% level of significance,
We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated
Step-by-step explanation:
Given the data in the question;
To test whether population proportion p is overstated;
Null hypothesis H₀ : p = (75%) = 0.75
Alternative hypothesis H₁ : = < (75%) < 0.75
now, sample proportion p" = 64 / 100 = 0.64
from the dot plot below, we will determine the p-value for test { P(p" < 0.64)}
so, the number of times p"<0.64 in 150 simulations is 5
Hence; P(p" < 0.64 ) = 5 / 150 = 0.0333
P-value = 0.0333
At 5% level of significance;
0.0333 < 0.05
Therefore, we reject null hypothesis H₀ at 5% level of significance,
We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated
This sample provide evidence that the grocery store manager overstated the true proportion P-value = 0.0333.
Given data in the question:
- To test whether population proportion p is overstated;
- Null hypothesis H₀ : p = (75%) = 0.75
- Alternative hypothesis H₁ : = < (75%) < 0.75
Now, sample proportion p" = 64 / 100 = 0.64
From the dot plot below,
- we will determine the p-value for test { P(p" < 0.64)}
- The number of times p"<0.64 in 150 simulations is 5
Therefore:
- P(p" < 0.64 ) = 5 / 150 = 0.0333
- P-value = 0.0333
At 5% level of significance;
0.0333 < 0.05
Therefore, we reject null hypothesis H₀ at 5% level of significance,
We conclude that proportion of shoppers who bought bananas at least once in the past month is overstated.
Learn more :
https://brainly.com/question/16437485?referrer=searchResults
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