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A concert venue has 20 seats in the first row and an 5 additional seats in each successive row. If there are 35 rows of seats then how many people can attend a sold-out show? 3,675 190 2,100

Sagot :

Answer:

3,675 people

Step-by-step explanation:

First row, a = 20

Common difference, d = 5

number of terms, n = 35

Sn = n/2 {2a + (n - 1)d}

= 35/2 {2*20 + (35 - 1)5}

= 35/2 {40 + ( 34)5}

= 17.5(40 + 170)

= 17.5(210)

= 3,675 people

The answer is actually 3675.

My reasoning: Plug it in and you shall see!