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Sagot :
Answer:
Hello your question is incomplete attached below is the complete question
answer :
Total charge enclosed within the sphere : [tex]\frac{q_{r1} }{4\pi e_{0}R^3 } . r[/tex]
Total charge enclosed outside the sphere : [tex]\frac{q}{4\pi e_{0}r^2 } .r[/tex]
Explanation:
Given data:
Total charge of a uniformly charged sphere = Q
radius = R
first step : find the electric field inside and outside the uniformly charged sphere
2nd step : determine the total charge enclosed within and outside the sphere
make a sketch of the uniformly charged sphere
Attached below is a detailed solution
![View image batolisis](https://us-static.z-dn.net/files/d37/9f33033ce555874a5b52e3053bdf36b0.png)
![View image batolisis](https://us-static.z-dn.net/files/dd4/35fd0cc16723049430ba288aca44d6e2.jpeg)
![View image batolisis](https://us-static.z-dn.net/files/d42/4ec4397aeb32324edfdeaf4b06890d9e.jpeg)
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