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Sagot :
Answer:
average rate of change of h(x) on −1 ≤ x ≤ 5 is then 5
Step-by-step explanation:
change in h(x)
average rate of change = ------------------------
change in x
Calculate h(x) at the interval endpoints: -1 ≤ x ≤ 5, and then subtract h(5) from h(-1):
h(5) = (5)² + 5 + 4 = 34
h(-1) = (-1)² -1 + 4 = 4
change in h(x) = 34 - 4 = 30
change in x: 5 - (-1) = 6 30
average rate of change of h(x) on −1≤x≤5 is then ------------- = 5
6
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