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Quadrilateral DEFG has vertices at D(3,4) E(8,6) F(9,9) G(4,7). Prove that DGEF is a parallelogram

Quadrilateral DEFG Has Vertices At D34 E86 F99 G47 Prove That DGEF Is A Parallelogram class=

Sagot :

MisterZeng
Sorry I’m kinda lazy to graph it but here are the ways you can prove a parallelogram:
Both pairs of opposite sides are parallel.
Both pairs of opposite sides are congruent.
Both pairs of opposite angles are congruent.
Diagonals bisect each other.
One angle is supplementary to both consecutive angles (same-side interior)
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