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Sagot :
Step-by-step explanation:
First car.
0.2 gallons used for 7 miles.
Distance drive on 1 gallon of gas [tex]=\dfrac{7}{0.2}=35\ \text{miles}[/tex]
Second car.
0.5 gallons used for 12 miles.
Distance drive on 1 gallon of gas [tex]=\dfrac{12}{0.5}=24\ \text{miles}[/tex]
Third car.
0.9 gallons used for 25 miles.
Distance drive on 1 gallon of gas [tex]=\dfrac{25}{0.9}=27.8\ \text{miles}[/tex]
So, the first car traveled fast while the second car traveled least. Hence, the sequence is first car > third car > second car.
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