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Sagot :
Answer:
The size (diameter) of the basketball's shadow on the wall is approximately 53.38 cm
Explanation:
The given parameters of the basketball are;
The diameter of the basketball = 23 cm (9 inches)
The distance of the light bulb from the closest side of the basketball = 3 m
The distance from the ball to the wall = 4 m
The distance from the light source to the center of the ball, d = 3 m + 0.23/2 m = 3.115 m
The angle the light ray makes with the edge of the ball, θ = arctan(0.115/3.115)
Therefore, the ratio of the shadow width divided by 2 to the distance from the light from the wall = 0.115/3.115
The distance from the light from the wall = 3 m + 4 m + 0.23 m = 7.23 m
Therefore;
((The width of the shadow)/2)/(The distance from the light from the wall) = 0.115/3.115
∴ ((The width of the shadow)/2)/(7.23 m) = 0.115/3.115
((The width of the shadow)/2) = 7.23 m × 0.115/3.115 = 16629/62300 m ≈ 0.2669 m = 26.69 cm
The width (diameter) of the shadow on the wall = 2 × 16629/62300 m ≈ 0.5338 m = 53.38 cm
The size (diameter) of the basketball's shadow on the wall ≈ 53.38 cm
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