Wenning0419
Answered

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How many moles of potassium sulfate are present in a sample that weighs 45.8g?

I do not understand how to solve this please help ​

Sagot :

SvetkaChem

Answer:

0.263 mol

Explanation:

K2SO4 - potassium sulfate

Molar mass (K2SO4) = 2*39.0983 + 32.065 + 4*15.9994 =

= 174.2592≈174.26 g/mol

45.8 g * 1 mol/174.26 g = 0.263 mol

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