Answered

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Does the physical form of the material matter for mass-mole
and mole-mass calculations?

Sagot :

babysumeya7
Tin metal reacts with hydrogen fluoride to produce tin(II) fluoride and hydrogen gas according to the following balanced equation.

Sn(s)+2HF(g)→SnF2(s)+H2(g)
Sn(s)+2HF(g)→
SnF
2
(s)+
H
2
(g)

How many moles of hydrogen fluoride are required to react completely with 75.0 g of tin?

Step 1: List the known quantities and plan the problem.

Known

given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
1 mol Sn = 2 mol HF (mole ratio)
Unknown

mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.

g Sn → mol Sn → mol HF

Step 2: Solve.

75.0 g Sn×1 mol Sn118.69 g Sn×2 mol HF1 mol Sn=1.26 mol HF
75.0 g Sn×
1
mol Sn
118.69
g Sn
×
2
mol HF
1
mol Sn
=1.26 mol HF

Step 3: Think about your result.

The mass of tin is less than one mole, but the 1:2 ratio means that more than one mole of HF is required for the reaction. The answer has three significant figures because the given mass has three significant figures.

The physical form of the material matter for mass-mole and mole-mass calculations is solid.

What is the relation between mass & moles?

Relation between mass and moles will be represented as:

n = W/M, where

W = given mass in grams

M = molar mass in grams/mole

So the physical state of the matter that is used in the above relation is solid because solid is only present in the grams and kilogrmas quantity.

Hence solid is the physical form of the matter.

To know more about mass & moles, visit the below link:

https://brainly.com/question/15373263

#SPJ2

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