Answered

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Stephen rolls a fair dice 78 times. How many times would Stephen expect to roll a number greater than 2?

Sagot :

MrRoyal

Answer:

52 times

Step-by-step explanation:

Given

[tex]n = 78[/tex] -- Number of times

Required

Determine the expected times to get > 2.

In a fair dice, the outcome > 2 are:

[tex]>2 = \{3,4,5,6\}[/tex]

The probability of the above is:

[tex]p = \frac{4}{6}[/tex]

[tex]p = \frac{2}{3}[/tex]

The number of times is calculated using:

[tex]E(x) = n * p[/tex]

[tex]E(x) = 78* \frac{2}{3}[/tex]

[tex]E(x) = \frac{78* 2}{3}[/tex]

[tex]E(x) = \frac{156}{3}[/tex]

[tex]E(x) = 52[/tex]

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