Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

How to solve this maths problem?
Pls help​


How To Solve This Maths ProblemPls Help class=

Sagot :

Answer:

Step-by-step explanation:

(a) The length and breadth of the playground as measured by the surveyor are 20 m and 13 m respectively to nearest metre.

Since the actual length is x m and breadth is y m, then;

i.               x ≥ 20 m or x ≤ 20 m

ii.              y ≥ 13 m or y ≤ 13 m

(b) perimeter of the playground = 2 (length + breadth)

                                                     = 2 ( 20 + 13)

                                                     = 2 x 33

                                                     = 66 m

The range of values of the perimeter = 65.4 m < perimeter < 66.5 m

ii. area of the playground = length x breadth

                                          = 20 x 13

                                         = 260 [tex]m^{2}[/tex]

The range of values of the area = 259.4 [tex]m^{2}[/tex] < Area <  260.5 [tex]m^{2}[/tex]