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In need of help on Alg 2

In Need Of Help On Alg 2 class=

Sagot :

Answer:

[tex]\frac{20}{13}[/tex] + [tex]\frac{5}{13}[/tex] [tex]\sqrt{3}[/tex]

Step-by-step explanation:

Given

[tex]\frac{5}{4-\sqrt{3} }[/tex]

To rationalise the denominator, multiply the numerator/ denominator by the conjugate of the denominator.

The conjugate of 4 - [tex]\sqrt{3}[/tex] is 4 + [tex]\sqrt{3}[/tex]

= [tex]\frac{5(4+\sqrt{3}) }{(4-\sqrt{3})(4+\sqrt{3}) }[/tex]

= [tex]\frac{20+5\sqrt{3} }{16-3}[/tex]

= [tex]\frac{20+5\sqrt{3} }{13}[/tex]

= [tex]\frac{20}{13}[/tex] + [tex]\frac{5}{13}[/tex] [tex]\sqrt{3}[/tex]

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