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What is the percentage of water to the nearest tenth in this compound? Ba(OH)2 * 8H2O

Sagot :

mass of water: 8 * 18 g = 144 g
mass of Ba(OH)2 = 171.3 g

total mass: 144 g + 171.3 g =  315.3 g

percentage of water: (144 g / 315.3 g) * 100% = 45.67%