Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Elimination:
3x-4y=16
5x+6y=14

Sagot :

luana
[tex] \left \{ {{3x-4y=16\ \ | * (-5)} \atop {5x+6y=14 \ \ | *3}} \right. \\\\ \left \{ {{-15x+20y=-80} \atop {15x+18y=42}} \right. \\+-----\\add\ both \ equations\\\\ 38y=-38\ \ \ | divide\ by\ 38\\\\ y=-1\\\\ 3x=16+4y\\\\ x=\frac{16+4y}{3}=\frac{16+4*(-1)}{3}=\frac{12}{3}=4\\\\ \left \{ {{y=-1} \atop {x=4}} \right. [/tex]
okay for this one, i will start with x

3x - 4y = 16
5x + 6y = 14

I will multiply the top row with (-5) and the bottom with (3) 
so the new equation is

-15x + 20y = -80
15x + 18y = 42

After canceling (x) the new equation will be

38y = -38

Divide by 38

And you will get -1

Now substitute (-1) to (y)  to the old equation ( any of the old equation)
3x- 4(-1)= 16
x = 4

answers ( 4, -1)
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.