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pre calculus
cos(sin^-1(4/7))

Sagot :

valorusa112

Answer:

[tex]\frac{\sqrt{33} }{7}[/tex]

Step-by-step explanation:

Find the missing side of the right triangle by Pythagorean theorem:

[tex]7^{2} = 4^{2} + x^{2}[/tex]

[tex]x = \sqrt{33}[/tex]

The answer would be this over the hypotenuse.

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