Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

What is the area of a square if the half of the diagonal is 6

Sagot :

pangarcher500

Answer:

72

Step-by-step explanation:

Cut the square into two equal triangles along the diagonal

You know that half of the diagonal is 6 so multiply that by 2 to get 12 which is the hypotenuse of your triangles

Then use the pythagorean theorem to solve for the sides

a^2 + b^2 = 12^2

a^2 + b^2 = 144

Since the original shape was a square both sides a and b are equal

a^2 = b^2

a^2 + a^2 = 144

2a^2 = 144

a^2 = 144/2

a^2 = 72

a = [tex]\sqrt{72}[/tex]

Since a = b then a = [tex]\sqrt{72}[/tex] =b

Multiply both sides a and b to get the area of the square

[tex]\sqrt{72}[/tex] * [tex]\sqrt{72}[/tex] = 72

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.