fingertebello073
Answered

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Mr Abraham is able to divide the learners in his mathematics class into equal groups of 2, 5 or 6 without leaving any learners out. What is the smallest possible number of learners in the class​

Sagot :

marykeetonirlextra

Answer:

30

Step-by-step explanation:

Find the lowest number divisible by both 6, 5, and 2.

To start, let's list off the numbers divisible by six, and see if we can check any of them off for 5. Since both 2 and 6 are even numbers, we know that if a number is divisible by 6, it's divisible by 2.

6 12 18 24 30 36 42 48 54 60

All of these numbers are divisible by two. Let's find the lowest one that is divisible by 5. We know this by either the umber ending in 5 or 0.

30 is the lowest number that is divisible by 2, 5, or 6.

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