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PLEASE HELP ME! I AM STUCK AND THIS IS DUE IN 5 MINUTES! I WILL MARK BRAINIEST!!

5. Michel wants to buy his mother handmade chocolates for Mother’s Day. He has $15.00 to spend. The price of each type of chocolate is given below.
Fudge centres: $0.60 Nut clusters: $0.75 Truffles: $0.80

Michel has $15.00. How many of each type of chocolate can he buy if buys only one type? Show your work. *Hint: create an equation for each type*

Fudge centres: Nut clusters: Truffles:

Michel decides to buy all three types of chocolates, instead of choosing just one type. If Michel buys the same number of all three types, how many can he buy and stay within his budget? Show your work

Sagot :

AnimalPost

Answer:

25 fudge centres, 20 nut clusters, 18 truffles, 6 of each type of chocolate

Step-by-step explanation:

Michel has a total of $15.00

So, if he only has to buy one type, we just divide the total amount by the price, like this:

[tex]\frac{15.00}{0.60}[/tex] = 25 fudge centres

[tex]\frac{15.00}{0.75}[/tex] = 20 nut clusters

[tex]\frac{15.00}{0.80}[/tex] = 18.75, so we round down = 18 truffles

If he buys the same of number of each type, we know that:

0.60x + 0.75x + 0.80x ≤ $15.00

2.15x ≤ 15.00

x ≤ 6.977...

This means that Michel can only buy 6 of each type of chocolate.

annieflvs

Answer:

If he buys only one type, he can buy 25 fudge centers OR 20 nut clusters OR 18 truffles.

The equations you can write to solve those are:

0.6f = 15

0.75n = 15

0.8t = 15

If he buys an equal number of each then

0.6f + 0.75n + 0.8t = 15

and

f = n = t

He can buy 6 of each without going over his budget.

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