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You are decomposing 2.00 mol of baking soda according to the following equation:
2 NaHCO3 -> Na2CO3 + CO2 + H2O
If you only collected 0.750 mol of Na2CO3 after the reaction finished, what was the
percent yield?
75.0%
62.5%
37.5%
25.0%
Question 6 (1 point)
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You Are Decomposing 200 Mol Of Baking Soda According To The Following Equation 2 NaHCO3 Gt Na2CO3 CO2 H2O If You Only Collected 0750 Mol Of Na2CO3 After The Re class=

Sagot :

I’m not sure but I’m thinking 75.0% btw if you want an exact answer you need to offer more than 5 points