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Sagot :
Answer:
Part 1
Given equation:
- C(t) = -0.30 (t – 12)² + 40
For t = 0
- C(t) = -0.30 (0 - 12)² + 40
- C(t) = -0.30 (-12)² + 40
- C(t) = -3.2
For t = 12 (noon)
- C(t) = -0.30 (12 - 12)² + 40
- C(t) = -0.30 (0)² + 40
- C(t) = 40
For t = 24 (midnight)
- C(t) = -0.30 (24 - 12)² + 40
- C(t) = -0.30 (12)² + 40
- C(t) = -0.30 × 144 + 40
- C(t) = - 43.2 + 40
- C(t) = -3.2
Part 2
attached below
Part 3
- C(t) = –0.30(t – 12)² + 40
- F(t)=9/5C(t)+32
Substituting the values:
- F(t)=9/5{–0.30 (t – 12)² + 40}+32
- F(t) = -0.54 (t – 12)² + 72 + 32
- F(t) = -0.54 (t – 12)² + 104
5, 6 and 7, should be simplish
good luck, i hope this helps :)

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