Answer:
(2y+3)(3y+5)
Step-by-step explanation:
6y^2+19y+15
Factor the expression by grouping. First, the expression needs to be rewritten as 6y^2+ay+by+15. To find a and b, set up a system to be solved.
a+b=19
ab=6×15=90
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 90.
1,90
2,45
3,30
5,18
6,15
9,10
Calculate the sum for each pair.
1+90=91
2+45=47
3+30=33
5+18=23
6+15=21
9+10=19
The solution is the pair that gives sum 19.
a=9
b=10
Rewrite 6y^2+19y+15 as (6y^2+9y)+(10y+15).
(6y^2+9y)+(10y+15)
Factor out 3y in the first and 5 in the second group.
3y(2y+3)+5(2y+3)
Factor out common term 2y+3 by using distributive property.
(2y+3)(3y+5)
