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Write the ratios for sin x, cos x and tan x

Write The Ratios For Sin X Cos X And Tan X class=

Sagot :

Answer:

sin(x)=[tex]\sqrt{119\\}[/tex] / 12, cos(x)=5/12, tan=[tex]\sqrt{119\\}[/tex] / 5

Step-by-step explanation:

segment YZ is length a, we need to find a

segment XZ is length 5

segment XY is length 12

XYZ is a right triangle, so a^2 + b^2 = z^2, so

a^2 + 5^2 = 12^2, simplify

a^2 + 25 = 144, subtract 25

a^2 = 119

a = [tex]\sqrt{119\\}[/tex]

then we can determine all the trig ratios

soh - cah - toa

sin = opp/hyp, cos=adj/hyp, tan=opp/adj

sin(x)=[tex]\sqrt{119\\}[/tex] / 12, cos(x)=5/12, tan=[tex]\sqrt{119\\}[/tex] / 5