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What is an equation of the line that passes through the points (0,5) and (-5,7) Put your answer in fully reduced form

Sagot :

Answer:

y = 2/5x + 5

Step-by-step explanation:

I assume you want the equation in point slope form? So assuming that, (0, 5) is the y intercept which is b in the equation y=mx+b (b=5). Now you have to find the slope, paper is really handy (I like drawing a graph out to help me sometimes but an easy way to do it is another equation like this...

y2-y1/x2-x1=

7-5/-5-0=

2/5 --> So 2/5 is the slope, and that finishes the equation

Final equation in point slope form: y=2/5x+5

HOPE YOU UNDERSTAND NOW!!!! :)

The equation of the line that passes through the point (0, 5) and (-5, 7) is

y = - 2/5 x + 5

The equation can be represented in the slope intercept form below

  • y = mx + b

where

m = slope

b = y- intercept

(0, 5)(-5, 7)

The slope can be found below

m = 7 - 5 / -5 - 0  = 2 / -5 = - 2/5

Therefore, using y = mx + b format

y = -2/5 x + b

let's find b using the coordinate  (0, 5)

5 = - 2 /5 (0) + b

b = 5

Finally, the equation is

y = - 2/5 x + 5

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