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A right circular cone is shown. The base of the cone is a circle with the center at point A. The Distance from point A to point C is 16 inches. The distance from point C to point B is 20 inches.

A Right Circular Cone Is Shown The Base Of The Cone Is A Circle With The Center At Point A The Distance From Point A To Point C Is 16 Inches The Distance From P class=
A Right Circular Cone Is Shown The Base Of The Cone Is A Circle With The Center At Point A The Distance From Point A To Point C Is 16 Inches The Distance From P class=
A Right Circular Cone Is Shown The Base Of The Cone Is A Circle With The Center At Point A The Distance From Point A To Point C Is 16 Inches The Distance From P class=

Sagot :

Answer:

6.4

Step-by-step explanation:

The distance between the point A and B is 12 inches which is the radius of the cone. Thus, The diameter of the cone will be 24 inches.

What is Pythagoras Theorem?

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

[tex]|AC|^2 = |AB|^2 + |BC|^2[/tex]

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

A right circular cone is shown.

The base of the cone is a circle with the center at point A.

The Distance from point A to point C is 16 inches.

The distance from point C to point B is 20 inches.

[tex]|BC|^2 = |AB|^2 + |AC|^2 \\\\|20|^2 = |AB|^2 + |16|^2 \\\\AB = \sqrt{400 - 256}\\\\AB = \sqrt{144} \\\\AB = 12[/tex]

Therefore, the distance between the point A and B is 12 inches which is the radius of the cone.

Thus, The diameter of the cone will be 24 inches.

Learn more about Pythagoras' theorem here:

https://brainly.com/question/12105522

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