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Two butterflies simultaneously leave an aster flowerbed and fly to a rose flowerbed. One butterfly flies 10 m/min faster than the other, and so lands on a rose 1 minute earlier. Find the speed of each butterfly if the flowerbeds are 560m apart

Sagot :

MrRoyal

The speed of the first butterfly is 70 m/min, while the speed of the second butterfly is 80 m/min

Represent the speed of the first butterfly with x.

Given that the flowerbeds are 560 meters apart, and rate of one butterfly is 10m/min greater than the other

Then, we have:

[tex]B_1 = \frac{560}{x}[/tex]

[tex]B_2 = 1 + \frac{560}{x+10}[/tex]

Equate both equations

[tex]1 + \frac{560}{x+10} = \frac{560}{x}[/tex]

Using a graphing calculator, we have:

[tex]x = 70[/tex]

Also, we have:

[tex]x + 10 = 80[/tex]

This means that, the speed of the first butterfly is 70 m/min, while the speed of the second butterfly is 80 m/min

Read more about speed and rates at:

https://brainly.com/question/19493296

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