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A chemist working for Udensi industries wants to create a new ink for tattoos and cosmetics. Determine the theoretical yield of iron (ll) sulfide if the chemist uses 22.5 grams of iron ? Type of rxn : AD , SR, DR , D Type of calculation : mol to mol ; mol to mass ; mass to mols mass to mass Fe S8--> Fes

A Chemist Working For Udensi Industries Wants To Create A New Ink For Tattoos And Cosmetics Determine The Theoretical Yield Of Iron Ll Sulfide If The Chemist Us class=

Sagot :

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Answer:

35.36 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

8Fe + S₈ —> 8FeS

Next, we shall determine the mass of Fe that reacted and the mass of FeS produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 8 × 56 = 448 g

Molar mass of FeS = 56 + 32 = 88 g/mol

Mass of FeS from the balanced equation = 8 × 88 = 704 g

SUMMARY:

From the balanced equation above,

448 g of Fe reacted to produce 704 g of FeS.

Finally, we shall determine the theoretical yield of FeS as follow:

From the balanced equation above,

448 g of Fe reacted to produce 704 g of FeS.

Therefore, 22.5 g of Fe will react to produce = (22.5 × 704)/448 = 35.36 g of FeS.

Thus, the theoretical yield of FeS is 35.36 g

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