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A 18 g ball is swung at a 1m long string.It revolves every 1 s,what is the magnitude of swing's tension?

Sagot :

onyebuchinnaji

Answer:

The magnitude of swing's tension is 0.71 N.

Explanation:

Given;

mass of the ball, m = 18 g = 0.018 kg

angular speed of the ball, ω = 1 rev/s

radius of the motion, r = 1 m

Angular speed in rad/s is calculated as follows;

[tex]\omega = \frac{2\pi \ rad}{rev} \times \frac{1 \ rev}{s} \\\\\omega = 2 \pi \ rad/s[/tex]

Linear speed of the ball, v;

v = ωr

v = 2π x 1

v = 2π  m/s

The magnitude of swing's tension is calculated as the centripetal force keeping the ball in circular motion.

[tex]F_c =T = \frac{mv^2}{r} \\\\T= \frac{0.018 \ \times (2\pi )^2}{1} \\\\T = 0.71 \ N[/tex]

Therefore, the magnitude of swing's tension is 0.71 N.

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