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In ΔMNO, the measure of ∠O=90°, the measure of ∠N=26°, and NO = 5.1 feet. Find the length of OM to the nearest tenth of a foot .

Sagot :

Answer:

x=2.4874≈2.5 feet

Step-by-step explanation:

tanN=

adjacent

opposite

​

=

5.1

x

​

\tan 26=\frac{x}{5.1}

tan26=

5.1

x

​

5.1\tan 26=x

5.1tan26=x

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